## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - Test: Chapter 4: 7

#### Answer

$6a^{5}b^{3}$

#### Work Step by Step

Using the laws of exponents, the given expression, $\dfrac{24a^7b^4}{20a^2b} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4}\cdot6a^{7-2}b^{4-1}}{\cancel{4}\cdot5} \\\\= 6a^{5}b^{3} .\end{array}

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