Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4: 37

Answer

$24$

Work Step by Step

Substituting $x$ with $-3$ and $y$ with $2$, the given expression, $ 2x^2y-3y^2 ,$ evaluates to \begin{array}{l}\require{cancel} 2(-3)^2(2)-3(2)^2 \\\\= 2(9)(2)-3(4) \\\\= 36-12 \\\\= 24 .\end{array}
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