Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4 - Page 300: 12



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{9x^3y^2}{3x^8y^{-3}} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{3}\cdot3x^{3-8}y^{2-(-3)}}{\cancel{3}} \\\\= 3x^{-5}y^{5} \\\\= \dfrac{3y^{5}}{x^5} .\end{array}
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