## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - Test: Chapter 4 - Page 300: 13

#### Answer

$\dfrac{b^{4}}{16a^{12}}$

#### Work Step by Step

Using the laws of exponents, the given expression, $(2a^3b^{-1})^{-4} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{-4}a^{3(-4)}b^{-1(-4)} \\\\= 2^{-4}a^{-12}b^{4} \\\\= \dfrac{b^{4}}{2^{4}a^{12}} \\\\= \dfrac{b^{4}}{16a^{12}} .\end{array}

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