Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Test: Chapter 4: 13

Answer

$\dfrac{b^{4}}{16a^{12}}$

Work Step by Step

Using the laws of exponents, the given expression, $ (2a^3b^{-1})^{-4} ,$ is equivalent to \begin{array}{l}\require{cancel} 2^{-4}a^{3(-4)}b^{-1(-4)} \\\\= 2^{-4}a^{-12}b^{4} \\\\= \dfrac{b^{4}}{2^{4}a^{12}} \\\\= \dfrac{b^{4}}{16a^{12}} .\end{array}
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