## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$6b^2+7b-5$
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of 2 binomials, the product of the given expression, $(3b+5)(2b-1) ,$ is \begin{array}{l}\require{cancel} 3b(2b)+3b(-1)+5(2b)+5(-1) \\\\= 6b^2-3b+10b-5 \\\\= 6b^2+7b-5 .\end{array}