Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.3 Geometric Sequences and Series - 14.3 Exercise Set - Page 912: 60

Answer

$\frac{4}{33}$

Work Step by Step

$0.12121212\ldots $ This can be written as, $0.12121212\ldots =0.12+0.0012+0.000012+\cdots $ This is an infinite geometric series: ${{a}_{1}}=0.12$ and ${{a}_{2}}=0.0012$. So, the value of $\left| r \right|$ is, $\begin{align} & \left| r \right|=\left| \frac{0.0012}{0.12} \right| \\ & =\left| 0.01 \right| \\ & =0.01 \end{align}$ We know that ${{S}_{\infty }}=\frac{{{a}_{1}}}{1-r}$. $\begin{align} & {{S}_{\infty }}=\frac{{{a}_{1}}}{1-r} \\ & =\frac{0.12}{1-0.01} \\ & =\frac{0.12}{0.99} \\ & =\frac{4}{33} \end{align}$ Thus, the fraction notation of the decimal number $0.12121212\ldots $ is $\frac{4}{33}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.