## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$a_n=\frac{1}{x}\times\frac{1}{x}^{n-1}=(\frac{1}{x})^{n}$
The general term in a geometric sequence is: $a_n=a_1\times r^{n-1}$ Here, $a_1=\frac{1}{x}$ We can find the common ratio by dividing two subsequent terms: $r=\frac{a_2}{a_1}=\frac{\frac{1}{x^2}}{\frac{1}{x}}=\frac{x}{x^2}=\frac{1}{x}$ The general term is: $a_n=\frac{1}{x}\times\frac{1}{x}^{n-1}=\frac{1}{x}^{n}$