Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.3 Geometric Sequences and Series - 14.3 Exercise Set - Page 912: 49

Answer

No, the infinite geometric series does not have a limit.

Work Step by Step

The provided series is $4-6+9-\frac{27}{2}+\cdots $. Here, ${{a}_{1}}=4$, $n=\infty $ and $\begin{align} & r=\frac{-6}{4} \\ & =-\frac{3}{2} \end{align}$ Since $\left| r \right|=\frac{3}{2}$ is not less than 1, ${{S}_{\infty }}$doesn’t exist. Thus, the infinite geometric series $3+15+75+\cdots $ does not have a limit.
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