## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t$
Using $\log_bx^m=m\log_bx$ or the Power Rule of Logarithms, the given expression, $\log_{Q}Q^{t} ,$ is equivalent to \begin{array}{l}\require{cancel} t\log_{Q}Q .\end{array} Since $\log_QQ=1,$ the expression, $t\log_{Q}Q ,$ simplifies to \begin{array}{l}\require{cancel} t(1) \\\\= t .\end{array}