## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$1.792$
Using the properties of logarithms, the given expression, $\log_b 3b ,$ is equivalent to \begin{array}{l}\require{cancel} \log_b 3+\log_b b .\end{array} Since it is given that $\log_b 3=0.792$ and that $\log_b b=1,$ the expression above, $\log_b 3+\log_b b$, evaluates to \begin{array}{l}\require{cancel} 0.792+1 \\\\= 1.792 .\end{array}