Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.4 Properties of Logarithmic Functions - 12.4 Exercise Set: 66

Answer

$1.792$

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_b 3b ,$ is equivalent to \begin{array}{l}\require{cancel} \log_b 3+\log_b b .\end{array} Since it is given that $\log_b 3=0.792 $ and that $\log_b b=1,$ the expression above, $ \log_b 3+\log_b b $, evaluates to \begin{array}{l}\require{cancel} 0.792+1 \\\\= 1.792 .\end{array}
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