Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.4 Properties of Logarithmic Functions - 12.4 Exercise Set: 64

Answer

$\dfrac{1}{2}$

Work Step by Step

Using the properties of logarithms, the given expression, $ \log_b \sqrt{b} ,$ is equivalent to \begin{array}{l}\require{cancel} \log_b b^{1/2} \\\\= \dfrac{1}{2}\log_b b .\end{array} Since $\log_b b=1,$ the expression above, $ \dfrac{1}{2}\log_b b $, evaluates to \begin{array}{l}\require{cancel} \dfrac{1}{2}(1) \\\\= \dfrac{1}{2} .\end{array}
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