## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\log_a13$
Using $\log_b x-\log_b y=\log_b \dfrac{x}{y}$ (or the logarithm of a quotient), the given logarithmic equation, $\log_a 26-\log_a 2 ,$ is equivalent to \begin{array}{l}\require{cancel} \log_a \dfrac{26}{2} \\\\ \log_a13 .\end{array}