Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 725: 55

Answer

$\frac{233}{2}$.

Work Step by Step

$\sqrt{2x-8}=15$ Squaring both sides of the equation, $\begin{align} & \sqrt{2x-8}=15 \\ & {{\left( \sqrt{2x-8} \right)}^{2}}={{\left( 15 \right)}^{2}} \\ & 2x-8=225 \end{align}$ Add $\left( 8 \right)$ to both sides. $\begin{align} & 2x-8=225 \\ & 2x-8+8=225+8 \\ & 2x=233 \end{align}$ Divide by $2$ on both sides, $\begin{align} & 2x=233 \\ & \frac{2x}{2}=\frac{233}{2} \\ & x=\frac{233}{2} \end{align}$ Thus, the required value is $x=\frac{233}{2}$.
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