Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 725: 49

Answer

Marti’s fall will not take twice as long as Rafe’s.

Work Step by Step

Assume that Rafe’s cord length is $s$. Therefore, Marti’s cord length will be $2s$. The expression used to calculate the time taken in a free fall will be, $4.9{{t}^{2}}=s$ Substitute the values in the above expression, $4.9{{t}^{2}}=s$ Divide both the sides by $49$, $\begin{align} & \frac{4.9{{t}^{2}}}{4.9}=\frac{s}{4.9} \\ & {{t}^{2}}=\frac{s}{4.9} \end{align}$ Apply roots on both the sides, $\begin{align} & \sqrt{{{t}^{2}}}=\sqrt{\frac{s}{4.9}} \\ & t=\frac{s}{2.21} \end{align}$ Marti’s cord length will be $2s$. $\begin{align} & \sqrt{{{t}^{2}}}=\sqrt{\frac{2s}{4.9}} \\ & t=\frac{s}{1.56} \end{align}$ Thus, Marti’s fall will not take twice as long as Rafe’s.
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