Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 725: 47

Answer

$11$ days

Work Step by Step

Let $t$ represent the number of days taken to plant the trees by Katherine. Juliana takes $t+2$ hours. In one day, Katherine does $\frac{1}{t}$ of the job and Julianna does $\frac{1}{t+2}$ of the job. Convert to equations: Working together, Katherine and Julianna can plant trees in $6$ days. According to the provided statement, the equation is, $\begin{align} & 6\left( \frac{1}{t} \right)+6\left( \frac{1}{t+2} \right)=1 \\ & \frac{6}{t}+\frac{6}{t+2}=1 \end{align}$ Solve: Multiply by the LCD $t\left( t+2 \right)$ on both sides of the equation, $\begin{align} & t\left( t+2 \right)\left( \frac{6}{t}+\frac{6}{t+2} \right)=t\left( t+2 \right)1 \\ & 6\left( t+2 \right)+6t=t\left( t+2 \right) \\ & 6t+12+6t={{t}^{2}}+2t \\ & 0={{t}^{2}}-10t-12 \end{align}$ Using the quadratic formula, $\begin{align} & t=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\ & =\frac{-\left( -10 \right)\pm \sqrt{{{\left( -10 \right)}^{2}}-4\left( 1 \right)\left( -12 \right)}}{2\left( 1 \right)} \\ & =\frac{10\pm \sqrt{100+48}}{2} \\ & =\frac{10\pm \sqrt{148}}{2} \end{align}$ Thus, the values of t are; $\begin{align} & t=\frac{10+2\sqrt{37}}{2}\text{ and }t=\frac{10-2\sqrt{37}}{2} \\ & t\approx 11.082\text{ and }t\approx -1.0827 \\ \end{align}$ Thus, it would take 11 days.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.