Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 725: 52

Answer

$-\frac{1}{8}$

Work Step by Step

$\frac{1}{x}=-8$ Multiply by $x$ on both sides. $\begin{align} & \frac{1}{x}\times x=\frac{-8}{1}\times x \\ & 1=-8x \end{align}$ Divide by $\left( -8 \right)$ on both sides. $\begin{align} & 1=-8x \\ & \frac{1}{-8}=\frac{-8x}{-8} \\ & -\frac{1}{8}=x \end{align}$ Thus, the required value is $x=-\frac{1}{8}$.
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