Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 694: 62



Work Step by Step

We solve the equation using the rules of exponents and radicals. Note, if we wanted to check our solution, we could plug the value we get back into the original equation to see if it yields a true statement. Solving the equation, we find: $$ \left(\sqrt{11x+\sqrt{6+x}}\right)^2=6^2\\ 11x+\sqrt{6+x}=36\\ \left(\sqrt{6+x}\right)^2=\left(36-11x\right)^2\\ x=3$$ Note, there is a second solution, but it is not true when plugged back into the expression.
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