Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 694: 54

Answer

$6+i$

Work Step by Step

Removing the grouping symbols and then combining the real parts and the imaginary parts, the given expression is equivalent to \begin{array}{l}\require{cancel} (9-7i)-(3-8i) \\\\= 9-7i-3+8i \\\\= (9-3)+(-7i+8i) \\\\= 6+i .\end{array}
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