# Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 53

$-2-9i$

#### Work Step by Step

Removing the grouping symbols and then combining the real parts and the imaginary parts, the given expression is equivalent to \begin{array}{l}\require{cancel} (-4+3i)+(2-12i) \\\\= -4+3i+2-12i \\\\= (-4+2)+(3i-12i) \\\\= -2-9i .\end{array}

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