Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 694: 47


$5\sqrt{2} \text{ } cm$

Work Step by Step

The diagonal and 2 sides of the square form a right triangle. Let $c$ be the hypotenuse and $a,b$ be the equal legs. Using $a^2+b^2=c^2$ or the Pythagorean Theorem, where $c=10$ and $a=b,$ then \begin{array}{l}\require{cancel} a^2+b^2=c^2 \\\\ a^2+a^2=10^2 \\\\ 2a^2=100 \\\\ a^2=\dfrac{100}{2} \\\\ a^2=50 \\\\ a=\sqrt{50} \\\\ a=\sqrt{25\cdot2} \\\\ a=\sqrt{(5)^2\cdot2} \\\\ a=5\sqrt{2} .\end{array} Hence, the side of the square (which has the same value as the legs) is equal to $ 5\sqrt{2} \text{ } cm .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.