#### Answer

$\dfrac{6+4i}{13}$

#### Work Step by Step

Multiplying by the conjugate of the denominator, the given expression, $
\dfrac{2}{3-2i}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{2}{3-2i}\cdot\dfrac{3+2i}{3+2i}
\\\\=
\dfrac{2(3)+2(2i)}{(3)^2-(2i)^2}
\\\\=
\dfrac{6+4i}{9-4i^2}
\\\\=
\dfrac{6+4i}{9-4(-1)}
\\\\=
\dfrac{6+4i}{9+4}
\\\\=
\dfrac{6+4i}{13}
.\end{array}