Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set: 36

Answer

$-27$

Work Step by Step

Using $i^2=-1$, the given expression, $ 3i\cdot9i ,$ simplifies to \begin{array}{l}\require{cancel} 27i^2 \\\\= 27(-1) \\\\= -27 .\end{array}
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