Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set: 29

Answer

$7+2i$

Work Step by Step

Removing the grouping symbols and then adding the real parts and the imaginary parts, the given expression, $ (9+5i)-(2+3i) ,$ simplifies to \begin{array}{l}\require{cancel} 9+5i-2-3i \\\\= (9-2)+(5i-3i) \\\\= 7+2i .\end{array}
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