# Chapter 10 - Exponents and Radicals - 10.8 The Complex Numbers - 10.8 Exercise Set - Page 686: 32

$-4-5i$

#### Work Step by Step

Removing the grouping symbols and then adding the real parts and the imaginary parts, the given expression, $(5-3i)-(9+2i) ,$ simplifies to \begin{array}{l}\require{cancel} 5-3i-9-2i \\\\= (5-9)+(-3i-2i) \\\\= -4-5i .\end{array}

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