#### Answer

$\left( 3,4 \right)$

#### Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$, or the Midpoint Formula, the midpoint of the segment joining $\left(
-2,5
\right) \text{ and } \left(
8,3
\right),$ is
\begin{array}{l}\require{cancel}
\left( \dfrac{-2+8}{2},\dfrac{5+3}{2} \right)
\\\\=
\left( \dfrac{6}{2},\dfrac{8}{2} \right)
\\\\=
\left( 3,4 \right)
.\end{array}