Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.7 The Distance Formula, the Midpoint Formula, and Other Applications - 10.7 Exercise Set: 68

Answer

$\left( 0,-\dfrac{1}{2} \right)$

Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, the midpoint of the segment joining $\left( -1,2 \right) \text{ and } \left( 1,-3 \right),$ is \begin{array}{l}\require{cancel} \left( \dfrac{-1+1}{2},\dfrac{2+(-3)}{2} \right) \\\\= \left( \dfrac{0}{2},\dfrac{-1}{2} \right) \\\\= \left( 0,-\dfrac{1}{2} \right) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.