Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.7 The Distance Formula, the Midpoint Formula, and Other Applications - 10.7 Exercise Set: 67

Answer

$\left( \dfrac{7}{2},\dfrac{7}{2} \right)$

Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, the midpoint of the segment joining $\left( 2,-1 \right) \text{ and } \left( 5,8 \right),$ is \begin{array}{l}\require{cancel} \left( \dfrac{2+5}{2},\dfrac{-1+8}{2} \right) \\\\= \left( \dfrac{7}{2},\dfrac{7}{2} \right) .\end{array}
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