#### Answer

$d\approx200.003
\text{ units}
$

#### Work Step by Step

Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ or the Distance Formula, the distance, $d$, between the given points, $\left(
0.5,100
\right) \text{ and } \left(
1.5,-100
\right),$ is
\begin{array}{l}\require{cancel}
d=\sqrt{ \left(0.5-1.5 \right)^2+\left( 100-(-100) \right)^2}
\\\\
d=\sqrt{ \left(-1 \right)^2+\left( 200 \right)^2}
\\\\
d=\sqrt{ 1+40,000}
\\\\
d=\sqrt{ 40,001}
\\\\
d\approx200.003
\text{ units}
.\end{array}