## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - 10.2 Rational Numbers as Exponents - 10.2 Exercise Set - Page 641: 80

#### Answer

$\dfrac{1}{27}$

#### Work Step by Step

Using the laws of exponents, the given expression, $\left( 27^{-2/3} \right)^{3/2} ,$ simplifies to \begin{array}{l}\require{cancel} 27^{\left( -\frac{2}{3} \right) \left( \frac{3}{2} \right)} \\\\= 27^{\left( -\frac{6}{6} \right)} \\\\= 27^{-1} \\\\= \dfrac{1}{27^1} \\\\= \dfrac{1}{27} .\end{array}

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