Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.2 Rational Numbers as Exponents - 10.2 Exercise Set - Page 641: 109



Work Step by Step

Solving the equation by canceling out the denominators and simplifying, we obtain: $$ \frac{15}{x}x\left(x+2\right)-\frac{15}{x+2}x\left(x+2\right)=2x\left(x+2\right)\\ 15\left(x+2\right)-15x=2x\left(x+2\right)\\ x=3,\:x=-5$$
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