## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$3b\sqrt[7]{a^5}$
Using the laws of exponents, the given expression, $\dfrac{3b}{a^{-5/7}} ,$ is equivalent to \begin{array}{l}\require{cancel} 3ba^{5/7} .\end{array} Using $a^{m/n}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m$, the expression, $3ba^{5/7},$ simplifies to \begin{array}{l}\require{cancel} 3b\sqrt[7]{a^5} .\end{array}