#### Answer

$(x^3y^2z^2)^{1/7}$

#### Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m$, the given expression, $
\sqrt[7]{x^3y^2z^2}
,$ is equivalent to
\begin{array}{l}\require{cancel}
(x^3y^2z^2)^{1/7}
.\end{array}

Published by
Pearson

ISBN 10:
0-32184-874-8

ISBN 13:
978-0-32184-874-1

$(x^3y^2z^2)^{1/7}$

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