Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 76: 50



Work Step by Step

The given expression, $ -\dfrac{3}{5}\div\left(-\dfrac{4}{15} \right) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{-3(-4)}{5(15)} \\\\= \dfrac{-\cancel{3}(-4)}{5(\cancel{3}\cdot5)} \\\\= \dfrac{4}{25} .\end{array}
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