## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{5}{12}$
Cancelling the common factor between the numerator and the denominator, the given expression, $\dfrac{20}{48}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4}\cdot5}{\cancel{4}\cdot12} \\\\= \dfrac{5}{12} .\end{array}