## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1: 44

#### Answer

$-\dfrac{14}{10}$

#### Work Step by Step

The given expression, $-\dfrac{9}{10}-\dfrac{1}{2}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{1(-9)-5(1)}{10} \\\\= \dfrac{-9-5}{10} \\\\= \dfrac{-14}{10} \\\\= -\dfrac{14}{10} .\end{array}

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