# Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 76: 32

$\dfrac{27}{25}$

#### Work Step by Step

Multiplying the numerators and the denominators, the given expression, $\dfrac{9}{10}\cdot\dfrac{6}{5}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{9(6)}{10(5)} \\\\= \dfrac{9(\cancel{2}\cdot3)}{\cancel{2}\cdot5(5)} \\\\= \dfrac{27}{25} .\end{array}

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