Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 76: 29

Answer

$\dfrac{19}{24}$

Work Step by Step

Using the $LCD= 24 $, the given expression, $ \dfrac{5}{12}+\dfrac{3}{8} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{2(5)+3(3)}{24} \\\\= \dfrac{10+9}{24} \\\\= \dfrac{19}{24} .\end{array}
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