Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test - Page 431: 15


$4\sqrt 6$

Work Step by Step

Recall the following rule: $\sqrt{x^{2}}=x$. Thus, we obtain: $\sqrt 8 \times \sqrt {12}$ =$\sqrt {8\times12}$ =$\sqrt {96}$ =$\sqrt {16\times6}$ =$\sqrt {4^{2}}\times\sqrt 6$ =$4\times\sqrt 6$ =$4\sqrt 6$
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