Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test - Page 431: 10



Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt{\dfrac{24}{36}} ,$ evaluates to (nearest tenth) \begin{array}{l}\require{cancel} \sqrt{\dfrac{\cancel{12}\cdot2}{\cancel{12}\cdot3}} \\\\= \sqrt{\dfrac{2}{3}} \\\\= \sqrt{\dfrac{2}{3}\cdot\dfrac{3}{3}} \\\\= \sqrt{\dfrac{6}{9}} \\\\= \dfrac{\sqrt{6}}{\sqrt{9}} \\\\= \dfrac{\sqrt{6}}{3} .\end{array}
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