Answer
$\dfrac{\sqrt{6}}{3}$
Work Step by Step
Using the properties of radicals, the given expression, $
\sqrt{\dfrac{24}{36}}
,$ evaluates to (nearest tenth)
\begin{array}{l}\require{cancel}
\sqrt{\dfrac{\cancel{12}\cdot2}{\cancel{12}\cdot3}}
\\\\=
\sqrt{\dfrac{2}{3}}
\\\\=
\sqrt{\dfrac{2}{3}\cdot\dfrac{3}{3}}
\\\\=
\sqrt{\dfrac{6}{9}}
\\\\=
\dfrac{\sqrt{6}}{\sqrt{9}}
\\\\=
\dfrac{\sqrt{6}}{3}
.\end{array}
