Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test: 9

Answer

$\dfrac{5\sqrt{2}}{2}$

Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt{\dfrac{25}{2}} ,$ evaluates to \begin{array}{l}\require{cancel} \sqrt{\dfrac{25}{2}\cdot\dfrac{2}{2}} \\\\= \sqrt{\dfrac{25}{4}\cdot2} \\\\= \sqrt{\left( \dfrac{5}{2} \right)^2\cdot2} \\\\= \dfrac{5}{2}\sqrt{2} \\\\= \dfrac{5\sqrt{2}}{2} .\end{array}
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