Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test: 11

Answer

$\dfrac{\sqrt{10}}{4}$

Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt{\dfrac{5}{8}} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{5}{8}\cdot\dfrac{2}{2}} \\\\= \sqrt{\dfrac{10}{16}} \\\\= \dfrac{\sqrt{10}}{\sqrt{16}} \\\\= \dfrac{\sqrt{10}}{\sqrt{(4)^2}} \\\\= \dfrac{\sqrt{10}}{4} .\end{array}
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