Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test: 5

Answer

$\approx 2.1$

Work Step by Step

Using $\sqrt{2}=1.41$ and the properties of radicals, the given expression, $ \dfrac{3}{\sqrt{2}} ,$ evaluated to the nearest tenth, is equal to: \begin{array}{l}\require{cancel} \dfrac{3}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} \\\\= \dfrac{3\sqrt{2}}{(\sqrt{2})^2} \\\\= \dfrac{3\sqrt{2}}{2} \\\\= \dfrac{3(1.41)}{2} \\\\ \approx 2.1 .\end{array}
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