Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test - Page 431: 5


$\approx 2.1$

Work Step by Step

Using $\sqrt{2}=1.41$ and the properties of radicals, the given expression, $ \dfrac{3}{\sqrt{2}} ,$ evaluated to the nearest tenth, is equal to: \begin{array}{l}\require{cancel} \dfrac{3}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}} \\\\= \dfrac{3\sqrt{2}}{(\sqrt{2})^2} \\\\= \dfrac{3\sqrt{2}}{2} \\\\= \dfrac{3(1.41)}{2} \\\\ \approx 2.1 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.