Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5: 30

Answer

$n=\dfrac{1}{3}$

Work Step by Step

Squaring both sides of the equation and then using the properties of equality, we obtain: \begin{array}{l}\require{cancel}\left( \sqrt{5n-1} \right)^2=\left( \sqrt{2n} \right)^2 \\\\ 5n-1=2n \\\\ 5n-2n=1 \\\\ 3n=1 \\\\ n=\dfrac{1}{3} .\end{array} Upon checking, $ n=\dfrac{1}{3} $ satisfies the original equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.