## Elementary Algebra

Published by Cengage Learning

# Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5 - Page 424: 23

#### Answer

$y=\dfrac{21}{4}$

#### Work Step by Step

Squaring both sides of the equation and then using the properties of equalities, we obtain: \begin{array}{l}\require{cancel}\left( 2\sqrt{y+1} \right)^2=\left( 5 \right)^2 \\\\ 4(y+1)=25 \\\\ 4y+4=25 \\\\ 4y=25-4 \\\\ 4y=21 \\\\ y=\dfrac{21}{4} .\end{array}

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