Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5 - Page 424: 22

Answer

x=17/4

Work Step by Step

Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 8x-6=4x+11. We now simplify: $ 4x-6=11 \\\\4x=17 \\\\ x=17/4 $ We now must check our solution: $\sqrt{8(17/4)-6}=\sqrt{4(17/4)+11} \\\\ \sqrt{28}=\sqrt{28}$ This is true, so our solution is valid.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.