## Elementary Algebra

We first add 4 to both sides of the equation to obtain that $\sqrt{4n-3}=4$. Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 4n-3=16. We add 3 on both sides and then divide both sides of the equation by 4 to isolate n and obtain: n=19/4. We now must check our solution: $\sqrt{4(19/4)-3}-4 = 0 \\\\\ \sqrt {16}-4=0 \\\\ 0=0$ This is true, so n=19/4.