Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5: 14

Answer

n=19/4

Work Step by Step

We first add 4 to both sides of the equation to obtain that $\sqrt{4n-3}=4$. Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 4n-3=16. We add 3 on both sides and then divide both sides of the equation by 4 to isolate n and obtain: n=19/4. We now must check our solution: $\sqrt{4(19/4)-3}-4 = 0 \\\\\ \sqrt {16}-4=0 \\\\ 0=0$ This is true, so n=19/4.
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