## Elementary Algebra

Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 7x-3=4x+3. We now simplify: $3x-3=3 \\\\ 3x=6 \\\\ x=2$ We now must check our solution: $\sqrt{7(2)-3}=\sqrt{4(2)+3} \\\\ \sqrt{11}=\sqrt{11}$ This is true, so our solution is valid.