Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5: 21

Answer

x=2

Work Step by Step

Recall, in order to cancel out a square root, we square both sides of the equation. Thus, we square both sides of the equation to obtain that 7x-3=4x+3. We now simplify: $ 3x-3=3 \\\\ 3x=6 \\\\ x=2$ We now must check our solution: $\sqrt{7(2)-3}=\sqrt{4(2)+3} \\\\ \sqrt{11}=\sqrt{11}$ This is true, so our solution is valid.
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