Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 79

Answer

$\frac{x+7}{(2x-1)(3x+1)}$

Work Step by Step

By inspection, we see that the LCM of the denominators is $(2x-1)(3x+1)$. Therefore, we create a common denominator using this LCM and obtain: $\frac{3}{2x-1}-\frac{4}{3x+1}$ =$\frac{3(3x+1)-4(2x-1)}{(2x-1)(3x+1)}$ =$\frac{9x+3-8x+4)}{(2x-1)(3x+1)}$ =$\frac{x+7}{(2x-1)(3x+1)}$
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