Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3 - Page 292: 73



Work Step by Step

By inspection, we see that the LCM of the denominators is $x(2x+1)$. Therefore, we create a common denominator using this LCM and obtain: $\frac{6}{x}-\frac{12}{2x+1}$ =$\frac{6(2x+1)-12(x)}{x(2x+1)}$ =$\frac{12x-12x+6}{x(2x+1)}$ =$\frac{6}{x(2x+1)}$
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