Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 7 - Algebraic Fractions - 7.3 - Adding and Subtracting Algebraic Fractions - Problem Set 7.3: 67

Answer

$\frac{10x-35}{x(x-5)}$

Work Step by Step

By inspection, we see that the LCM of the denominators is $x(x-5)$. Therefore, we create a common denominator using this LCM and obtain: $\frac{3}{x-5}+\frac{7}{x}$ =$\frac{x(3)+7(x-5)}{x(x-5)}$ =$\frac{3x+7x-35}{x(x-5)}$ =$\frac{10x-35}{x(x-5)}$
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